Xmas Spirit
Contents
We get given challenge.py
and encrypted.bin
. Analysing challenge.py
:
And appends the result of that as the encrypted character in encrypted.bin
.
Analysis
Gives us
So we can form two equations here using this information:
We subtract (2) from (1) to get that
Solution
And the resulting PDF has the flag HTB{4ff1n3_c1ph3r_15_51mpl3_m47h5}
within.
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