# Divisibility, Factors and Euclid's Algorithms

An outline of the fundamentals of number theory

Cryptography is built on the foundations of algebra and number theory, which we will hopefully cover well enough here.

$a$

is said to be divisible by $b$

if there is another integer $c$

such that $a=bc$

. In this case, $b$

is said to be a **factor**of$a$

. This is denoted by $a \mid b$

if $a$

divides $b$

, and $a \nmid b$

if it does not.Given two integers

$a$

and $b$

, the greatest common divisor $gcd(a,b)$

(also known as the highest common factor) is the largest integer $p$

where $p \mid a$

and $p \mid b$

.Given

$a$

and $b$

, we can write an equation linking the two:$a = b \cdot q + r$

Where

$q$

and $r$

are integers which fit the equation with $r < b$

. Basically, $b$

divides into $a$

a maximum of $q$

times with a remainder of $r$

. But here's where the trick lies.Every term added together in that equation must be divisible by

$gcd(a,b)$

because if we treat the gcd as $g$

we can say that $a=k_1g,b=k_2g$

:$k_1g = k_2g \cdot q + r$

Meaning

$r$

has to be some integer multiple of $g$

.But now, if we think outside the box, we realise that both

$b$

and $r$

are divisible by $gcd(a,b)$

... so we can just calculate $gcd(b, r)$

!This is quite a leap forward which will require a bit of thinking, but let's break it down algebraically:

$a = b \cdot q_0 + r_1 \\
b = r_1 \cdot q_1 + r_2 \\
r_1 = r_2 \cdot q_2 + r_3 \\
r_2 = r_3 \cdot q_3 + r_4 \\$

And so on. But when does it stop? When do we stop taking the GCD? Well we can stop taking the GCD once

$r_n = 0$

, in which case $r_{n-1} \mid r_{n-2}$

and as a result we can take $r_{n-1}$

as the GCD!I highly recommend you think about this for a bit until it makes sense to you, and make sure to use other resources if it helps!

Let’s say we want to find the GCD of 8075 and 16283. First, we can write it in the form

$a= b \cdot q+r$

:$16283 = 8075·2 + 133$

And now we attempt to calculate the GCD of 8075 and 133.

$8075 = 133 \cdot 60 + 95 \\
133 = 95 \cdot 1 + 38 \\
95 = 38 \cdot 2 + 19 \\
38 = 19 \cdot 2 + 0$

Therefore the GCD of 16283 and 8075 is 19.

We can take the Euclidean Algorithm a step further and calculate, in addition to the GCD,

$u,v \in \mathbb{Z}$

for $a,b$

which sum to the GCD, i.e.$au + bv = gcd(a,b)$

This extension of the algorithm is invaluable for calculating

**modular inverses**of numbers and is based on using the Euclidean Algorithm to calculate the GCD then writing it in terms of other numbers, repeating the process for the smallest non-GCD number until we reach an equation with only the GCD and the two starting numbers. Let's work with the example above, writing an equation for the GCD:$19 = 95 - 38 \cdot 2$

Now 38 is the smallest non-GCD number, and we can write it in terms of the larger number in the sequence of equations written in the example, then repeat for the next smallest:

$19 = 95 - 38 \cdot 2 \\
= 95 - (133 - 95 \cdot 1) \cdot 2 \\
= 95 - (133 \cdot 2 + 95 \cdot -2) \\
= 95 \cdot 3 + 133 \cdot -2 \\
= (8075 + 133 \cdot -60) \cdot 3 + 133 \cdot -2 \\
= 8075 \cdot 3 + 133 \cdot -180 + 133 \cdot -2 \\
= 8075 \cdot 3 + 133 \cdot -182 \\
= 8075 \cdot 3 + (16283 + 8075 \cdot -2) \cdot -182 \\
= 8075 \cdot 3 + 16283 \cdot -182 + 8075 \cdot 364 \\
= 8075 \cdot 367 + 16283 \cdot -182$

Therefore our equation

$au + bv = gcd(a,b)$

is as follows:$16283 \cdot -182 + 8075 \cdot 367 = 19$

Last modified 1yr ago